Let's move everything to the left side and distribute the two
x^2 -2x-8>0
(x-4)(x+2)>0
We can see that the two zeroes are at x=4 and x=-2, neither of which are solutions! They are important because we can use them to determine what segment(s) of the number line contain our solution set. Let's try testing 3 numbers, one that is greater than our two zeroes, one that is less than our two zeroes, and one that is between our zeroes.
Greater than: I'll choose x=1000 because it will make it easy to determine if our inequality holds. Note that when you substitute a large number like this it makes both factors of our quadratic positive, which guarantees our inequality is true.
Between: I choose x=0 because it is easy to calculate. (0-4)(0+2)>0 is equivalent to -8>0 which is clearly false.
Less than: let's pick a big negative number. It really does not matter what it is but when we select any large negative number we get two negative facts which result in a positive produce which guarantees our inequality is satisfied
Therefore our solution set is x>4 or x<-2