A telephone company offers two long-distance plans.
For how many minutes of long-distance calls would plan B be financially advantageous?
Let the minutes be represented by "t." So we're trying to find where
6 + .12t < 25 + .05t Subtract 6 from both sides
.12t < 19 + .05t Subtract .05t from both sides
.07t < 19 divide both sides by .07
t < 271.4
So basically......if we talk more than about 271 minutes, Plan A is cheaper......
Ill help you set it up and then you can try to solve it. We know we are trying to figure out when plan b is cheaper so
B<A
6+.12x<25+.05x
Let the minutes be represented by "t." So we're trying to find where
6 + .12t < 25 + .05t Subtract 6 from both sides
.12t < 19 + .05t Subtract .05t from both sides
.07t < 19 divide both sides by .07
t < 271.4
So basically......if we talk more than about 271 minutes, Plan A is cheaper......
Sally, you should try to understand all of these answers.
If you can understand how algebraic and graphing solutions work side by side it will make a lot of things more easily understood.
It is an important conceptual step I think.
If you want more help understanding please do not hesitate to ask.