A telephone company offers two long-distance plans.

Plan A: $25 per month and 5¢ per minute

Plan B: $6 per month and 12¢ per minute

Plan B: $6 per month and 12¢ per minute

For how many minutes of long-distance calls would plan B be financially advantageous?

sally1 Jun 26, 2014

#2**+13 **

Let the minutes be represented by "t." So we're trying to find where

6 + .12t < 25 + .05t Subtract 6 from both sides

.12t < 19 + .05t Subtract .05t from both sides

.07t < 19 divide both sides by .07

t < 271.4

So basically......if we talk more than about 271 minutes, Plan A is cheaper......

CPhill Jun 26, 2014

#1**+13 **

Ill help you set it up and then you can try to solve it. We know we are trying to figure out when plan b is cheaper so

B<A

6+.12x<25+.05x

jboy314 Jun 26, 2014

#2**+13 **

Best Answer

Let the minutes be represented by "t." So we're trying to find where

6 + .12t < 25 + .05t Subtract 6 from both sides

.12t < 19 + .05t Subtract .05t from both sides

.07t < 19 divide both sides by .07

t < 271.4

So basically......if we talk more than about 271 minutes, Plan A is cheaper......

CPhill Jun 26, 2014

#4**+3 **

Sally, you should try to understand all of these answers.

If you can understand how algebraic and graphing solutions work side by side it will make a lot of things more easily understood.

It is an important conceptual step I think.

If you want more help understanding please do not hesitate to ask.

Melody Jun 27, 2014