+0

# Solve the linear inequality.

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963
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A telephone company offers two long-distance plans.

Plan A: \$25 per month and 5¢ per minute
Plan B:  \$6 per month and  12¢ per minute

For how many minutes of long-distance calls would plan B be financially advantageous?

Jun 26, 2014

#2
+124676
+13

Let the minutes be represented by "t."  So we're trying to find where

6 + .12t < 25 + .05t   Subtract 6 from both sides

.12t < 19 + .05t          Subtract .05t from both sides

.07t < 19        divide both sides by .07

t < 271.4

So basically......if we talk more than about 271 minutes, Plan A is cheaper......

Jun 26, 2014

#1
+576
+13

Ill help you set it up and then you can try to solve it.  We know we are trying to figure out when plan b is cheaper so

B<A

6+.12x<25+.05x

Jun 26, 2014
#2
+124676
+13

Let the minutes be represented by "t."  So we're trying to find where

6 + .12t < 25 + .05t   Subtract 6 from both sides

.12t < 19 + .05t          Subtract .05t from both sides

.07t < 19        divide both sides by .07

t < 271.4

So basically......if we talk more than about 271 minutes, Plan A is cheaper......

CPhill Jun 26, 2014
#3
+33266
+8

Alan Jun 26, 2014
#4
+118117
+3

Sally, you should try to understand all of these answers.

If you can understand how algebraic and graphing solutions work side by side it will make a lot of things more easily understood.

It is an important conceptual step I think.

If you want more help understanding please do not hesitate to ask.

Jun 27, 2014