You have to make this more clear. Are we solving x in terms of y or vice versa? I am going to assume that it is in terms of y.

What is \(\frac{y-5}{2}<-\frac{x}{3}\) ?

Multiply 6 on both sides to get \(3y-15<-2x\)

Divide -2 on both sides, but we have to change the sign \(-\frac{3}{2}y+\frac{15}{2}>x\)