We have 10 standard 6-sided dice, all different colors. In how many ways can we roll them to get a sum of 20?
@Melody, if I solve the answer before you do, I will remember to get on here and check your answer! I'm sorry you think I'm rude.
There are 85,228 ways of getting 20 when rolling 10 dice. The probability of rolling a total of 20 is:
85,228 / (6^10) =85,228 / 60,466,176 =0.00140951 x 100=0.140951%.
The calculations for these odds are exactly the same as calculating the coefficient of x^20 in the expansion of this: (x+x^2+x^3+x^4+x^5+x^6)^10. So that x^20 =85,228x^20.
To read about this in detail, see this page of "Mathworld": http://mathworld.wolfram.com/Dice.html
I'm not sure I understand the website. Can you rephrase it so it is simpler?
I found out that we must find how many ways are there to give out 20 dots to 10 dice. Try simplifying that and find a pattern... I'm working on that right now
CPhill can explain it much better than I can. He can show you how to calculate the coefficient of x^20 in the expansion of the above sequence.
You still have not responded to my last answer even though I specifically requested you to.
That was 2.5 weeks ago. Why would I bother responding to this new question?
Here is your question posted here and the answers. Go through it in detail:
This is the one I was actually referring to: