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# what is (y-5)/2<-x/3

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what is (y-5)/2<-x/3

EKC4000  Sep 24, 2017
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You have to make this more clear. Are we solving x in terms of y or vice versa? I am going to assume that it is in terms of y.

What is $$\frac{y-5}{2}<-\frac{x}{3}$$ ?

Multiply 6 on both sides to get $$3y-15<-2x$$

Divide -2 on both sides, but we have to change the sign $$-\frac{3}{2}y+\frac{15}{2}>x$$

Jeff123  Sep 24, 2017
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Hi Jeff

You maths is fine but you have not made either x or y the subject.

Yours is fine, you only had to put x on the left hand side

what is (y-5)/2<-x/3

Make x the subject:

$$(y-5)/2<-x/3\\ \frac{3(y-5)}{2}<-x\\ \frac{-3(y-5)}{2}>x\\ x<\frac{-3(y-5)}{2}\\ or\\ x<\frac{3(5-y)}{2}\\$$

Make y the subject

$$\frac{y-5}{2}<\frac{-x}{3}\\ y-5<\frac{-2x}{3}\\ y<-\frac{2x}{3}+5\\$$

Melody  Sep 24, 2017