+0  
 
0
260
2
avatar+10 

what is (y-5)/2<-x/3

EKC4000  Sep 24, 2017
 #1
avatar+109 
+2

You have to make this more clear. Are we solving x in terms of y or vice versa? I am going to assume that it is in terms of y.

 

 

What is \(\frac{y-5}{2}<-\frac{x}{3}\) ?

 

Multiply 6 on both sides to get \(3y-15<-2x\)

 

Divide -2 on both sides, but we have to change the sign \(-\frac{3}{2}y+\frac{15}{2}>x\)

Jeff123  Sep 24, 2017
 #2
avatar+92805 
+1

Hi Jeff

You maths is fine but you have not made either x or y the subject.

Yours is fine, you only had to put x on the left hand side  wink

 

what is (y-5)/2<-x/3

 

Make x the subject:

\((y-5)/2<-x/3\\ \frac{3(y-5)}{2}<-x\\ \frac{-3(y-5)}{2}>x\\ x<\frac{-3(y-5)}{2}\\ or\\ x<\frac{3(5-y)}{2}\\\)

 

Make y the subject

 

\(\frac{y-5}{2}<\frac{-x}{3}\\ y-5<\frac{-2x}{3}\\ y<-\frac{2x}{3}+5\\ \)

Melody  Sep 24, 2017

6 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.