jugoslav

Hello, Guest!

Such a pyramid is impossible!!! 

The total slant area of a pyramid cannot be smaller than the area of its base!!!

Make sure that your numbers are correct.

The triangle is an isosceles triangle. The height is 6 with the altitude bisecting the base. The base is x while the sides of the triangle are unknown. The angles of the triangle on the base are both 60 degrees. I am supposed to use the Pythagorean theorem to find x the base of the triangle.

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h = 6         ∠θ = 60º        x = ?

(x / 2)² = (h / sin∠θ)² - h²

x = 6.92820323  or   x = 4√3 

https://web2.0calc.com/questions/plzzzzz-halp#r2

In the diagram below, ∠PQR = ∠PRQ = ∠STR = ∠TSR, RQ = 8, and SQ = 2. Find PQ.

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QR = QT = 8          XT = QS = 2           QL = 5            QZ = 4

XY = TL = sqrt( QT² - QL² ) = √39

∠PQR = tan^-1(√39 / 3)

PZ = tan∠PQR * QZ = 8.326663998

PQ = sqrt(QZ² + PZ²) = 9.237604326

https://web2.0calc.com/questions/what-is-the-general-solution-to-the-equation-tan-2cos-tan

this might help

Hi, Guest!

The area of an equilateral triangle is  ( √3 / 4) * 4²    ==> 6.92820323 square units

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2 (a/√3) + a = 4        a = 1.856406461          a² = 3.446244947

2 (b/√3) + b = a        b = 0.861561236          b² = 0.742287764

2 (c/√3) + c = b        c = 0.399851961          c² = 0.159881591

2 (d/√3) + d = c        d = 0.18557194            d² = 0.034436945

The sum of the areas of all squares         A = 4.382851247 square units

The side lengths of an equiangular octagon are 1, 2, 3, 4, 1, 2, 3, and 4 in clockwise order. Find the octagon's area.

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Since I couldn't find the correct answer on the web, I'll post my answer here.

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Octagon's area              A = 11 + 12√2        ( See diagram below)

Circles with radii 1 and 2 are inscribed in triangle ABC, as shown.  Find the area of triangle ABC.

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XY = 3       ZY = 1        WY = 2

∠BAW = sin^-1(1/3)

∠ABW = 90 - ∠BAW              ∠YBW = 1/2 (∠ABW)

BW = YW / tan(∠YBW)            AW = BW * tan(ABW)

[ABC] = AW * BW

Let ∠ABC = x, ∠BCD = 2x , and ∠CDE = 3x. If ∠BAE is 90º, what is the measure of ∠ABC in degrees?

https://web2.0calc.com/questions/please-help_54385

(Answered brilliantly by thelizzybeth, Jun 25, 2020)

Triangle ABC has vertices A(1, 0), B(0, −2), and C(3, −3). If triangle ABC is rotated 90º
counterclockwise about A, what are the coordinates of the image of C?

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The coordinates are  C(4, 2)