The triangle is an isosceles triangle. The height is 6 with the altitude bisecting the base. The base is x while the sides of the triangle are unknown. The angles of the triangle on the base are both 60 degrees. I am supposed to use the Pythagorean theorem to find x the base of the triangle.
+14903 Use the Pythagorean theorem to find x.
The triangle is an isosceles triangle. The height is 6 with the altitude bisecting the base. The base is x while the sides of the triangle are unknown. The angles of the triangle on the base are both 60 degrees. I am supposed to use the Pythagorean theorem to find x the base of the triangle.
Hello Guest!
\(Kosinus =\frac{Ankathete}{Hypotenuse}\)
\(cos(60^{\circ})=0.5=\large \frac{\frac{x}{2}}{s}\\ 0.5s= \frac{x}{2}\)
\(s=x\)
The Pythagorean theorem:
\(\color{blue}s^2=6^2+(\frac{x}{2})^2\\ s=x\\ x^2=36+\frac{x^2}{4}\\ x^2-\frac{x^2}{4}=36\)
\(\frac{3x^2}{4}=36\\ x^2=\frac{4\cdot 36}{3}=48\\ x^2=3\cdot 4^2\)
\(x=4\cdot \sqrt{3}\\ x=6.928\)
!
+1639 The triangle is an isosceles triangle. The height is 6 with the altitude bisecting the base. The base is x while the sides of the triangle are unknown. The angles of the triangle on the base are both 60 degrees. I am supposed to use the Pythagorean theorem to find x the base of the triangle.
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h = 6 ∠θ = 60º x = ?
(x / 2)2 = (h / sin∠θ)2 - h2
x = 6.92820323 or x = 4√3 
