jxc516

can you explain that answer?

thanks

formula for area of a trapezoid: a+b/2*h

so we plug in the bases and we have 70+65+1=136

136/2=68

1224/68=18

so our equation is 1224/((70 1/2+65 1/2)/2), or in Latex, \(\frac{1224}{\left(\frac{(141+131)}{2}\right)}\)

there are multiple answers...

we have the cycle of powers for 7 for above 3 is:

4. 1

5.7

6. 9

7. 3

4^3-(2*4)=64-8=56

oops did the wrong thing

it wasn't asking for the sum of the roots lol

well the answer is 7+6+13=26 :D

we have the area as 4/3*2^3

so 32/3*3.14 is about 33.49

we can expand to get 3x^2-7x=-3 which is the same as 3x^2-7x+3=0

we can now use vietas which gives us the answer of -7/3

we expand to get -6x-24y+10+34x+32y-8

we combine like terms to get 28x+8y+2

thanks!

volume of a sphere is \(\frac{4}{3}\pi r^2\)

plugging in 4, we have\(\frac{4}{3}\pi*(4^2)=\frac{4}{3}\pi*16=\frac{4*16}{3}\pi=\frac{64}{3}\pi\)

\(\frac{64}{3}\pi\approx\boxed{67.02}\)