Hello jxc! You know me (flec from aops)
Graphing quadratics can actually be very simple.
Let's use an example.
We plug in y as 0 to get the x-intercepts
Now for the vertex.
Vertex form is y = a(x – h)2 + k, where (h,k) is the vertex.
We rearrange \(y=x^2+6x+9\) to get it in this form, and we get the vertex.
Plot the vertex and two x-intercepts and you will get your parabola!