There are an infinite number of unit squares possible in a 4x4 square though, the squares do not have to be on lattice points.
Thanks for the help! I figured out the answer! :)
I multiplied everything by (a+b+c)(a+b)(a+c) and simplified it to where there is only one term on one side that is squared because that is like the cosine rule.
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I am sorry if they do.
So BC is \(\sqrt{19}\).
Then, by the law of sines, sin BCP is \(\frac{\sqrt3}{\sqrt{19}}\).
What now?
Sorry, but this answer is incorrect. Can you show how you got that?
I expanded it to \(a^2-2ab-2ac-b^2-c^2-bc=2a^2\).
I don't know how to compare that to the law of cosines: can I simplify further?
1) How would I find BC?
Taking the square root of 169, you get y = 13.
But we also have to remember that y can be negative, giving us that y = -13.
So our answers are y = 13, and y = -13.
Thank you so much! This makes a lot more sense!