Triangle \(ABC\) is isosceles with \(\overline{AB} = \overline{AC}\) and \(D\) is the midpoint of \(\overline{AB}\). If \(\angle BCD = \angle BAC = \theta,\) then find \(\cos \theta.\)
By the Law of Cosines on triangle ABC, cos theta works out to 2/3.
Sorry, but this answer is incorrect. Can you show how you got that?
Why should this person bother to help you more.
You have voted their first attempt to help you down.
Kick a person for offering help then ask for more help. Not usually a good tactic!
