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Triangle \(ABC\) is isosceles with \(\overline{AB} = \overline{AC}\) and \(D\) is the midpoint of \(\overline{AB}\). If \(\angle BCD = \angle BAC = \theta,\) then find \(\cos \theta.\)

 Jan 1, 2020
 #1
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By the Law of Cosines on triangle ABC, cos theta works out to 2/3.

 Jan 1, 2020
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Sorry, but this answer is incorrect. Can you show how you got that?

MathCuber  Jan 2, 2020
edited by MathCuber  Jan 2, 2020
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Why should this person bother to help you more.

You have voted their first attempt to help you down.  

 

Kick a person for offering help then ask for more help.  Not usually a good tactic!

Melody  Jan 2, 2020

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