Mathematician

It seems like what you need to do is simplify 676/260.

You can simplify it by dividing the top and the bottom by the same thing, until there's nothing left to evenly divide (divide with no remainder).

So for 676/260 the top and bottom can both be divided by 2:

676/260 =

(676/2)/(260/2) =

338/130

And for 338/130 the top and bottom can both be divided by 2 as well:

338/130 =

(338/2)/(130/2) =

169/65

And finally, for 169/65 the simplest form can be found by dividing both the top and the bottom by 13:

169/65 =

(169/13)/(65/13) =

the answer.

The two questions are:

1) 81 to the power of -2 to the power of -2

2) 81 to the power of (-2) to the power of -2

For 1), the expression can be represented numerically as \({81}^{{-2}^{-2}}\)

To solve, the first thing that can be done is simplify the -2^-2 above the 81.

-2^-2 =

-(2^-2) =

When you have a negative power, you do in this example 2^-n, you turn it into 1/2^n:

-(2^-2) =

-1/(2^2) =

-1/4

Now we have 81^-1/4, which can be solved as follows:

81^-1/4 =

\(\sqrt[4]{{81}^{-1}}\) =

\(\sqrt[4]{\frac{1}{81}}\) =

\(\frac{\sqrt[4]{1}}{\sqrt[4]{81}}\) =

\(\frac{1}{3}\)

For the second one, it's the same thing, except (-2)^-2:

(-2)^-2 =

1/((-2)^2) =

1/4

And then 81 ^ 1/4:

81^1/4 =

\(\sqrt[4]{{81}^{1}}\) =

3

"5/6 of 30" is the same thing as 5/6 times 30.

To multiply fractions, the numerator and denominator of each fraction is multiplied, and then simplified.

So:

\(\frac{5}{6} \times 30\) =

\(\frac{5}{6} \times \frac{30}{1}\) =

\(\frac{5\times 30}{6 \times 1}\) =

\(\frac{150}{6}\) = 25

You're welcome! Thanks for coming here to ask!

Yes, but it is also important to understand how to solve it without using the formula.

It's simpler not to bring in the quadratic formula in this case, since there's no "b" term.

It's probably better to understand the simplest way first before trying to use the formula to solve.

Okay, so we have "2i times 3i", which can be expressed numerically as:

2i * 3i

This also equals:

(2 * i) * (3 * i)

By the associative property:

(2 * i) * (3 * i)

2 * i * 3 * i

And by the commutative property:

2 * 3 * i * i

Now, we know what 2 * 3 equals:

2 * 3 * i * i

6 * i * i

And i = √-1

6 * i * i

6 * √-1 * √-1

Or:

6 * √-1 * √-1

6 * (√-1)^2

Square root of negative one is cancelled to form:

6 * (√-1)^2

6 * -1

Which simply equals -6.

I assume by "zero coordinates", you mean the coordinates of the x-intercepts or "zeroes" of the equation.

The first thing that can be done to find the zeroes is to factor out a 2 from both terms:

2x^2 - 3 = 0

2(x^2 - 3) = 0

x^2 - 3 = 0/2

x^2 - 3 = 0

Now, there are a couple of ways to go from here, but the simplest is probably adding 3 to both sides:

x^2 - 3 = 0

x^2 + 3 - 3 = 0 + 3

x^2 + (3 - 3) = 3

x^2 + 0 = 3

x^2 = 3

Then we can find the square root of both sides to isolate x:

x^2 = 3

√(x^2) = ±√3

It's important to remember that there's a plus or minus before the non-x term.

√(x^2) = ±√3

x = ±√3

x = √3 and x = -√3

Those are the roots.

Given that n does not have a given value, 3n + 2 is the simplest form of 3n + 2.

If you had a value that n equaled, 3n + 2 could be simplified further.

9^2 is 9 times itself two times.

9^2 = 9 * 9 = 81