Write the equation of a line that has a y-intercept of 3 and passes through the point (2,-4).
We just recently went over this in class, but I've forgotten and need a review.
A y intercept of 3 means the point (0, 3)...
Now note something.......we could find the slope arithmetically, but think about this....from (0,3) to (2, -4)...y changes by -7 and x changes by 2......and that's the definition of the slope....so...our slope is -7 / 2
Now....using the point slope form, we have
y - y1 = m(x - x1) where m is the slope and (x1, y1) is a point on the line....(let's use (0, 3))
So we have
y - 3 = (-7/2)(x - 0)
y - 3 = (-7/2)x add 3 to both sides
y = (-7/2)x + 3
And there you go !!!
A y intercept of 3 means the point (0, 3)...
Now note something.......we could find the slope arithmetically, but think about this....from (0,3) to (2, -4)...y changes by -7 and x changes by 2......and that's the definition of the slope....so...our slope is -7 / 2
Now....using the point slope form, we have
y - y1 = m(x - x1) where m is the slope and (x1, y1) is a point on the line....(let's use (0, 3))
So we have
y - 3 = (-7/2)(x - 0)
y - 3 = (-7/2)x add 3 to both sides
y = (-7/2)x + 3
And there you go !!!
Thanks...just missing "A y intercept of 3 means the point (0. 3)...". That is very helpful.