matthewmacdell

hmm.. this looks like an aops problem. thus, i will not give you the direct answer so you can learn! :))

check out this example: it's the same type of problem, just different numbers. i hope this helps!

https://web2.0calc.com/questions/help_68175 

you can create a ratio. the answer is 150 paperclips.

ah. sorry about that! i think i made a careless mistake :(( (even tho, of course i care! :))

initially,
g = number of girls;
b = number of boys.
Because the ratio of girls to boys is 3:1, therefore
g = 3b                 (1)

finally, we have
g-1 girls because one girl dropped the class;
b+3 boys because three more boys signed up.
Because the new ratio of girls to boys is 5:2, therefore
(g - 1)/(b + 3) = 5/2
Cross multiply.
2(g - 1) = 5(b + 3)
2g - 2 = 5b + 15
2g - 5b = 17            (2)

Substitute (1) into (2) to obtain
2(3b) - 5b = 17
b = 17
g = 3b = 3*17 = 51

Final number of students in the class = 17 + 51 = 68

Let A and B be the amount of money Alice and Bob have, respectively, at the beginning. We know that

A + n = 4(B - n)

A - n = 3(B + n)

Simplifying, we have

A + 5n = 4B

A = 3B + 4n

Subtracting the first equation from the second gives 5n = B - 4n, so B = 9n. Substituing this into the first equation gives A + n = 4(9n - n), from which we get A = 31n.

Therefore, the desired ratio is A/B = 31n/9n = 31/9.

hope this helped !

charis

i got it. thanks

i was wondering this question because if you used distributive property, you would get 8/8 = 1

how come it isn't 1?

sorry! i just wrote out all my work but it randomly got deleted. the answer is 8. here's how i got it:

first, i formulated two equations using the world problem:

x + y = 30

2x = 3y = 5.

then, i isolated the variables and used subsitution, then algebra, to find the value of y (which was 11, but it doesn't matter which you find first). then i found out x (which is 19). then, i found the positive difference. so the equation would be 19 - 11 = 8.

1. corroborate

3. extrapolate

i'm sorry i couldn't give you all the answers, but i'm almost 100% sure these two are correct.

i'm his sister! my name is actually charis but my user is matthew macdell based on a tv show character. thank you :))

fie! cometh h're and englut mine own coxcomb thee distemperate fooleth >:((

thee shouldst not calleth upon any oth'r nameth except charis

but i has't nay choice but to leaveth this questioneth because t looks liketh electric pavlov hast already answ'r'd t

nchang. thank you ! my point. we're tryna help each other out here.

yes. exactly

i was in prealgebra last year as well and this is the course i took afterwards, 'you know'.

ohh i didn't think of it that way. thanks !