+105 Find the number that can be placed in the empty space below so that the resulting quadratic is the square of a binomial:
x^2 + 22x + __
thanks !
+2094 Sorry I'm not CPhill.... but I'll try my best, too!
We know that in order to get a square of a binomial, we have to do (b/2)^2.
In this case, that will get us (22/2)^2 which is 121.
Therefore, we need to add 121 to each side, which will eventually get us (x+11)^2.
Hope this helped!
+37153 This is 'completing the square ' exercise'
take 1/2 of the 'x' coefficient then square it 11^2 = 121
x^2 + 22x + 121 = (x+11)2
+118687 Attn: CalTheGreat
There is only one side
This is NOT an equation.
All you are being asked is, 'what number do you need to add to x^2 +22x in order to make the expression a perfect square'.
the answer is \((\frac{22}{2})^2 = 11^2 = 121\)
\(x^2+22x+\boxed{121} = (x+11)^2\)
