+105 Let line1 be the graph of 3x + 4y = -14. Line2 is perpendicular to line1 and passes through the point (5,7). If line2 is the graph of the equation y=mx +b, then find m+b.
+36916 line 1 re-arranged y = -3/4 x -14/4 slope, m, is - 3/4 perpindicular slope = - 1/m = 4/3
line 2 y = 4/3 x +b put in point given
7 = 4/3 (5) + b resulting in b = 1/3
y = 4/3 x + 1/3 m = 4/3 b = 1/3 you can add them....
