+105 i just can't figure out how to split the $2 to jay and kay.
Jay, Kay, and Lee are hiking. Lee forgot to bring water. Jay brought 2 gallons of water and Kay brought 1.75 gallons of water. The three of them agree to divide all the water equally among them. Lee gives $2 for the water he receives, which Jay and Kay agree to divide fairly between the two of them. How much money should Jay receive?
Since Jay brought 2 gallons and Kay brought 1.75 gallons, Jay should get 2*2/(2 + 1.75) = 16/15 dollars. To the nearest cent, this is $1.07.
+23252 Together Jay and Kay brought 2.00 + 1.75 = 3.75 gallons.
To divide it equally among the three persons, each person will get 3.75 / 3 = 1.25 gallons.
Jay will give up 2.00 - 1.25 = 0.75 gallons (and keep 1.25 gallons).
Kay will give up 1.75 - 1.25 = 0.50 gallons (and keep 1.25 gallons).
Together, Jay and Kay will give up 1.25 gallons.
Jay gave up 0.75 gallons which is 0.75 / 1.25 = 0.60 or 60%.
Kay gave up 0.50 gallons which is 0.50 / 1.25 = 0.40 or 60%.
So, Jay should get 60% of the $2.00 ---> 0.60 x $2.00 = $1.20.
Kay should get 40% of the $2.00 ---> 0.40 x $2.00 = $0.80.
