Five standard six-sided dice are rolled. We are told there is no three-of-a-kind, but there is a pair of dice that show the same number. These two dice are set aside, and the other three dice are re-rolled. What is the probability that after re-rolling these three dice, at least three of the five dice show the same value?
To explain NinjaAnswer's answer:
Of the three dice rolled, one may match the original pair and two are different, and this can occur three ways: ( 1/6 x 5/6 x 5/6 ) + ( 5/6 x 1/6 x 5/6 ) + ( 5/6 x 5/6 x 1/6 ) = 75/216
[ where 1/6 is the probability of matching the first two and 5/6 is the probability of not matching the first two ]
Or, two may match the original pair and one is different:
( 1/6 x 1/6 x 5/6 ) + ( 1/6 x 5/6 + 1/6 ) + ( 5/6 x 1/6 x 1/6 ) = 15/216
Or, all three may match the original pair: ( 1/6 x 1/6 x 1/6 ) = 1/216
Or, all three may be the same, but not match the original pair:
( 5/6 x 1/6 x 1/6 ) = 5/216
[ where 5/6 is the probability of getting a new number and 1/6 is the probability of matching that new number ]
Adding these together: 75/216 + 15/216 + 1/216 + 5/216 = 96/216 = 4/9
Thanks geno3141:
This young person claims that he/she is 12 years old. No matter how precocious, I simply cannot believe that he/she is 12 years old!!.
Lol thanks! I actually am 12! I am a boy, by the way. Sorry I couldn't explain. Going back to school tomorrow and had to finish a bunch of stuff. I didn't have enough time. Sorry!