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Five standard six-sided dice are rolled. We are told there is no three-of-a-kind, but there is a pair of dice that show the same number. These two dice are set aside, and the other three dice are re-rolled. What is the probability that after re-rolling these three dice, at least three of the five dice show the same value?

 Jan 2, 2017
 #1
avatar+356 
+1

4/9

 Jan 3, 2017
 #2
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0

NinjaAnswer: Can you please explain your answer?

 Jan 3, 2017
 #3
avatar+23252 
+6

To explain NinjaAnswer's answer:

 

Of the three dice rolled, one may match the original pair and two are different, and this can occur three ways:  ( 1/6 x 5/6 x 5/6 ) + ( 5/6 x 1/6 x 5/6 ) + ( 5/6 x 5/6 x 1/6 )  =  75/216

[ where 1/6 is the probability of matching the first two and 5/6 is the probability of not matching the first two ]

 

Or, two may match the original pair and one is different:

                     ( 1/6 x 1/6 x 5/6 ) + ( 1/6 x 5/6 + 1/6 ) + ( 5/6 x 1/6 x 1/6 )  =  15/216

 

Or, all three may match the original pair:     ( 1/6 x 1/6 x 1/6 )  =  1/216

 

Or, all three may  be the same, but not match the original pair:

                      ( 5/6 x 1/6 x 1/6 )  =  5/216

[ where 5/6 is the probability of getting a new number and 1/6 is the probability of matching that new number ]

 

Adding these together:  75/216 + 15/216 + 1/216 + 5/216  =  96/216  =  4/9 

 Jan 3, 2017
 #4
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0

Thanks geno3141:

This young person claims that he/she is 12 years old. No matter how precocious, I simply cannot believe that he/she is 12 years old!!.

 Jan 3, 2017
 #5
avatar+356 
+1

Lol thanks! I actually am 12! I am a boy, by the way. Sorry I couldn't explain. Going back to school tomorrow and had to finish a bunch of stuff. I didn't have enough time. Sorry!sad

NinjaAnswer  Jan 3, 2017

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