how do u figure out 5^x = radical of 5
(evaluate log5radical5)
if you mean 5^x = sqrt(5) then:
x = 1/2
Because square roots are numbers raised to the 1/2 power.
Hope that helped
\(5^x = \sqrt5\\ x \log 5 = \log (\sqrt5)\\ x = \dfrac{\log(\sqrt5)}{\log 5}\)
Put this into the calculator and it is 1/2.
start by taking the log on both sides of the equation.
lg5(5^x) = lg5(sqr(5))