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avatar+131 

Equation 1: 3g+24=3(g+8)

Equation 2: 5c+9=5c-12

 Jan 2, 2017

Best Answer 

 #1
avatar+356 
+5

Equation 1: 3g+24=3(g+8)

 

3g+24=3(g+8)--------Simplify

 

3g+24 = 3g + 24------Subtract 3g + 24 from each side(you might relieze that there are infinitly many solutions from this step)

 

0 = 0 ---------Infinitly many solutions

 

Equation 2:  5c+9=5c-12

 

 5c+9=5c-12--------Subtract 5c from each side

 

9 =-12  ---------------Since 9 doesn't equal -12 then there are no solutions 

 

Equation 1 has infinitly many solutions

 

Equation 2 has no solutions

 Jan 2, 2017
 #1
avatar+356 
+5
Best Answer

Equation 1: 3g+24=3(g+8)

 

3g+24=3(g+8)--------Simplify

 

3g+24 = 3g + 24------Subtract 3g + 24 from each side(you might relieze that there are infinitly many solutions from this step)

 

0 = 0 ---------Infinitly many solutions

 

Equation 2:  5c+9=5c-12

 

 5c+9=5c-12--------Subtract 5c from each side

 

9 =-12  ---------------Since 9 doesn't equal -12 then there are no solutions 

 

Equation 1 has infinitly many solutions

 

Equation 2 has no solutions

NinjaAnswer Jan 2, 2017
 #2
avatar+129852 
0

Nice, Ninja.....!!!!!

 

 

cool cool cool

 Jan 2, 2017
 #3
avatar+356 
+5

Thanks CPhill!!cool

NinjaAnswer  Jan 2, 2017
 #4
avatar
0

Eq 1 (An identity has infinitely many solutions.)

 Jan 3, 2017

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