Thank you @textot ! This was exactly what i needed!
l=large pizza cost
m=medium pizza cost
d=drink cost
l=4d
m=2d
d=d
total money spent=4d+2d+d=7d
money left is $\boxed{30-7d}$
The digits repeat every 6 digits, so the 2007th digit is equal to the 3rd digit. The 3rd digit is 1, so your answer is $\boxed{1}$
Let $x=0.\overline{515}$.
Multiplying both sides by 1000 gives: $1000x=515.\overline{515}$
Subtract x from 1000x to get rid of the repeating part: $1000x-x=515$ so $999x=515$
Dividing both sides by 999 gives $\boxed{x=0.\overline{515}=515/999}$
$1/5+1/5^2+1/5^3=0.2+0.04+0.008=\boxed{0.248}$
$0.\overline{42}=42/99=14/33$, so we have $99/100*14/33=\boxed{\frac{21}{50}}$
sort of, people post questions, and other people answer them, so I guess it's like reddit for math. The only difference is here you get score for posting questions/answers and having them upvoted/downvoted and whatnot, so it's a bit different.
Thank you @CPhill!
If by $(\overline{345})$ you meant $0.(\overline{345})$, then the answer would be $0.(\overline{123+345})=0.(\overline{468})$. This means the sum of the digits in one repeating period is $4+6+8=\boxed{18}$
It says the solution is incorrect, but it won't give me the full answer. Can you show me all your work so I can look for mistakes?
