The proper divisors of 12 are 1, 2, 3, 4 and 6. A proper divisor of an integer $N$ is a positive divisor of $N$ that is less than $N$. What is the sum of the proper divisors of the sum of the proper divisors of 284?
(1, 2, 4, 71, 142, 284)>>Total = 6 divisors of 284
1 + 2 + 4 + 71 + 142 ==220 - Sum of the proper divisors.
Thank you! Although the problem asked for THE SUM of the proper divisors of the sum of the proper divisors, so the sum of the proper divisors of 220, I was able to take it from here, and got the answer 284.