+486 The proper divisors of 12 are 1, 2, 3, 4 and 6. A proper divisor of an integer $N$ is a positive divisor of $N$ that is less than $N$. What is the sum of the proper divisors of the sum of the proper divisors of 284?
(1, 2, 4, 71, 142, 284)>>Total = 6 divisors of 284
1 + 2 + 4 + 71 + 142 ==220 - Sum of the proper divisors.
+486 Thank you! Although the problem asked for THE SUM of the proper divisors of the sum of the proper divisors, so the sum of the proper divisors of 220, I was able to take it from here, and got the answer 284.
