sabi92

but x cant be 1 because the inequality needs to be higher than 0

thank you:)

Thats how i solved it(according to your recommendation to solve the top and bottom separately:

first of all:a≠2,3

x²-4x+4>0                              x²-4x+4<0

and                      or                and 

x-3>0                                      x-3<0

    ⇓   numenator:x²-4x+4=0          ⇓

                       (x-2)²=0

                         x=2

x ≠2                                         no x

x-3>0           denominator:

x>3                                           x<3

 so the answer:x>3

thanks but the answer which is written n my book is:x<-1 or x>2

Melody i have a question about the first step you've done.

i know that in problems like this we cant "cancel" the denominator so how did you get (1-x)(x-2)

the only reason i can think about is that we can get rid of the denominator by reducing x-2 and one of the brackets?is that what you've done?

melody thanks i think i've got it:)

so my way is wrong?

thanks to everyone)

heuruka if i am writing it this way:

a+x=xa

x-xa=-a

x(1-a)=-a

x=-a/(1-a)

the answer is incomplete then how do i get your answer?i need to divide it or  something?

But i've found x;exactly like melody did.is that wrong to find only x?the task is to solve the equation if its possible.so how can i know what do i need to find-x or a