1/x^2-1>1/x-1

I don't think the answer is correct as denominator would become zero if x = 0

Perhaps this graph will help:

You should really make use of brackets to clarify your expressions!

When x = 0 you have 1/(-1) > 1/(-1) or -1 > -1 which is not true!  So you are correct!

Are you sure the question had "greater than" not "greater than or equal to"?

The question is a bit confusing as you didn't specify when something ends, so the entirety of "2-1>1/x-1" could be the power you raise "x" to.

For it to even be possible for x to be 0 (as you claim that is the correct answer) without causing a math error, I have to assume you meant:

¹/_((x²)-1) > ¹/_(x-1)

However when x is 0 in this equation, all I get is "-1 > -1" which is a false statement.

I have to assume you have typo'd the question or answer somewhere as a result.

Alan that was a problem:for what x values the graph of function f(x)=1/x^2 wont be under the graph of function g(x)=1/x-1

so what i need to do is: 1/x^2-1>1/x-1

OHHH i've found my mistake.

 what i need to do is: 1/x^2-1>=1/x-1 ,

not 

 1/x^2-1>1/x-1

anyway,thanks to everyone who helped me:)