Scruffy23.

(a)

well since they can lay 7 miles of track every day, the formula i make for the amount of track there is left to lay is:

\(l=196-Ld\)

where l is the length of track remaining, L is the length of track they can lay in one day and d is the number of days.

so we replace L for 7 and d for 17 and we get:

\(l=196-7\times17\)

whichworks out to be 77 miles of track remaining to lay.

(b)

well since we want them to have 0 length of track remaining, and they can lay 7 miles of track a day, we can work out d. let's give the formula a bash to get:

\(d=\frac{196-l}{L}\)

we then replace l with 0 and L with 7 and get:

\(d=\frac{196}{7}\)

which works out to be 28. so it will take 28 days or 4 weeks for the railroad crew to lay 196 miles of track.

multiply out brackets:

3+15i-4i- -20

double negatives cancel out

3+15i-4i+20

move like terms together:

20+3+15i-4i-(2-i)

15i-4i = 11i

20+3+11i-(2-i)

*20+3=23*

23+11i-(2-i) or to avoid confusion (23+11i)-(2-i)

i can't squeeze anymore out of it so:

(3-4i)(1+5i)-(2-i) becomes 23+11i - (2-i) . peace.

so a²+b²=c²

subract a² from both sides

b² = c² - a²

square root both sides to get

b = sqrt(c² - a²)

so there you go. peace.

ooooooooh ok that make so much more sense now thanks 

yup that's the same proof i got :D

10% = 10/100 or 1/10

so basically if he gives away $256 then 256 is 1/10th of the money he earnt so the amount of money he earnt is 256*10 = $2560. peace.

well, since there are 5 of each letter and only five letters in a five letter word, then you could do five a's or five u's which is very useful. let us begin.

for the first letter there are 5 different letters to choose from and 1 letter in the word. this makes 5*1=5 1 letter words.

for two letters there is 5 letters for the first letter and another five for the second letter so that makes 5*5=25 2 letter words.

carry on until you get to five letters, where you get 5*5*5*5*5 or 5^5 different words which equals 3125 different five letter words.

so there you have it. there are 3125 different words in you could with five letters in your alphabet soup that only contains vowels for some silly hypothetical reason. peace. 

Goo'evening!

5444482

732(4/1.5)=x

732*(2+2/3)=x

(732*2)+(732*2/3)=x

1464+(732/3*2)=x

1464+244(2)=x

1464+488=x

x=1952