table for the given situation:
Given 1 day = 16 bars
days | # of bars |
1 | 16 |
2 | 32 |
3 | 48 |
4 | 64 |
5 | 80 |
6 | 96 |
7 | 112 |
8 | 128 |
9 | 144 |
Based on the table
no. of bars = 16 (# of days)
at no. of bars = 128, days = 8
Thus, it will take 8 days to complete the order
I will use backward approach.
At last, all three of them had
Same amount of money.
So, All of them had $360/3 = $120
Before the end, Ken gave 2/3 of his money to Laura. So, 3/5 of Ken's money = $120
Laura $120 | Tim $120 | Ken $120 <-- (End Step) |
$40 | $120 | $200 <-- (Previous Step) |
$40 | $210 | $110 --> (Step II) |
$80 | $170 | $110 --> (Initially) |
Ken's money in Previous Step = $200, Ken gave $80 to Laura. So, Laura's money in Previous Step = $(120 - 80) = $40
Step 2: - Tim gave 3/7 of his money to Ken.
So, 4/7 of Tim's money = $120
Tim's money in Step 2 = $210
Ken's money in Step 2 = $200 - $90 = $110 because Tim gave $90 to Ken.
Initially --> Laura gave half her money to Tim.
So, Laura's money initially = $40 * 2 = $80.
Tim's money initially = $(210 - 40) = $170
And, Ken's money initially = $110