Slimesewer

7 ingredients 

⁷c₁ + ⁷c₂ + ⁷c₃ + ⁷c₄ + ⁷c₅ + ⁷c₆ + ⁷c₇ 

7 + 21 + 35 + 35 + 21 + 7 + 1

      = 127 combos of ingredients 

1 type of bread: 5 options

          5 * 127 = 635 sandwiches

2 types of bread: ⁵c₂ = 10

         10 * 127 = 1270 sandwiches

635 + 1270 = 1905 sandwiches

=> for 24 cookies he need = 1 4/3 cups of sugar 

                               i.e 7/3 cups

                1 cookie he need = 7/3 / 24

                                            = 7/3 * 1/24

             for 18 cookies he need = 7/(3 * 24 4) * 18 * 3

                                                  = 7/4 cups 

                                            i.e 1 3/4 cups

No. of pieces Parker got candy = 11

Each of his friends got these times candy as he did.

So each of his friends got candy = 3 * 11 = 33

No. of pieces of candy get Parker and his friends = 11 + 33 + 33 + 33 = 110

expected number of defectives = probability of getting a defective * total number of calculators 

total calculators = 6 * 12 = 72

P(defect) = 2/12 = 1/6

expected defectives = 1/6 * 72 = 12

We assume Daniel collected x stamps

Peter collected y stamps

Ivan collected z stamps

So y + z + 9/16 (x + y + z)

     x + z = 3/4 (x + y + z)

     x + y = 55

x = 35

y = 20

z = 25

So z - y = 25 - 20 = 5

So the answer is 5 more stamps Ivan collected than Peter

George had $120 to buy new baseball.

Money spent on glove = 1/3 (120)⁴⁰ = 40

Moeny spent on bat = 1/4 (120)³⁰ = 30

Money spent on cap = 1/6 (120)²⁰ = 20

∴ Remaining money on basketball = 120 - (40 + 30 + 20)

                                                       = 120 - 90

Remaining money on baseballs = $30

Let Jacob and Nathan had x baseball cards

Jacob gave away 49 cards i.e. x - 49

Nathan gave away 85 cards i.e. x - 85

  Jacob = 5 Nathan

  x - 49 = 5 (x - 85) 

  x - 49 = 5x - 425

  x - 5x = -425 + 49

    -4x = -376 => x = 376/4 = 94

=> Jacob and Nathan had 94 baseball cards

Let Jake collected = x hats

Troy collected = 4x

Let David collected = y

Jake collected = y/2

y/2 = x => y = 2x

Also, x + 2x + 4x = 21

            7x = 21

              x = 3

Troy collected = 12

Jake collected less than Troy = 9 hats

let's call the money he initally had = $x

when he removes $12 from $x he had 3/7 of $x left

$x - $12 = 3/7 of $x

($x - $12) = $3x/7

7 ($x - 12) = $3x

$7x - $84 = $3x 

$7x - $3x = $84

$4x = $84

$x = 21

Therefore he initially had $21.

$21 - (how much spent) = (what's left)

$21 - $12 = $9.

$9 was left

Let Brian's initial amount be x

x - 8 = 2/3x

3 (x - 8) = 2x 

3x - 24 = 2x

3x - 2x = 24

x = 24

Amount left = 2/3x = 2/3 * 24

                   = 16

Brian has $16