Troy collected 4 times as many hats as Jake. Jake collected 1/2 as many hats as David. Altogether, they collected 21 hats. How many fewer hats did Jake collect than Troy?
How many fewer hats did Jake collect than Troy?
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\(t=4j\\ d=2j\\ t+j+d=21\\ 4j+j+2j=21\\ \color{blue}j=3\\ t=12\\ \color{blue}t-j=12-3=9 \)
9 fewer hats did Jake collect than Troy.
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Let Jake collected = x hats
Troy collected = 4x
Let David collected = y
Jake collected = y/2
y/2 = x => y = 2x
Also, x + 2x + 4x = 21
7x = 21
x = 3
Troy collected = 12
Jake collected less than Troy = 9 hats