SparklingWater2

15x12/2x4=360

360+12x12x6=360+864=$\boxed{1224 \ cm^3}$

there are (2010-2)/2+1=1005 circled red, and (2010-5)/5+1=402 circled blue, and there are (2010-10)/10+1=201 circled both blue and red, so

1005+402-201=$\boxed{1206}$ are circled once

sin $\theta$ = 4/5

cos $\theta$ = 3/5

tan $\theta$ = 4/3

csc $\theta$ = 5/4

sec $\theta$ = 5/3

cot $\theta$ = 3/4

there are 12 choose 5 = 792 possible ways of getting to point (5,7) from (0,0), and there are 7 choose 3=35 possible ways of getting to point (4,3) from (0,0), so the number of ways to get to (5,7) from (0,0) are

 792-35=$\boxed{757}$

f(f(x))=(f(x))^2+2f(x)=x^4+4x^3+6x^2+4x

we want to find all numbers where

x^2+2x=x^4+4x^3+6x^2+4x

 or where

x^4+4x^3+5x^2+2x=0=x(x^3+4x^2+5x+2)

we can divide both sides by x, and get

x^3+4x^2+5x+2=0

we can then write

(x^3+3x^2+2x)+1(x^2+3x+2)=x(x^2+3x^2+2x)+1(x^2+3x+2)=(x+1)(x+2)(x+1)

and we know that 0 is also a solution, so all the real numbers possible are

$\boxed{-2,-1,0}$

sigh* keep making those sloppy mistakes ;-;

y+5=1/3 x-4/3

y=1/3 x - 19/3

slope:$\boxed{\frac13}$

point on vertical line: $\boxed{0, -\frac{19}3}$

when x = 0,

y = 1/3 (0)-19/3= -19/3

point on horizontal line: $\boxed{19,0}$

when y=0,

0 = 1/3 x - 19/3

0 = x - 19

x = 19

Ooooh, thank you :) (I thought you should substitute t as 0 instead of the function :/)

we expand: x$\cdot$2x^2+x$\cdot$5x+x$\cdot$(-7)+(-3)$\cdot$2x^2+(-3)$\cdot$5x+(-3)$\cdot$(-7)=2x^3+5x^2-7x-6x^2-15x+21=$\boxed{2x^3-x^2-22x-21}$

we can substitute 2y for 2(2x-7), and we get

-5x+4x-14=-18

-x=-4

x=$\boxed{4}$

now, we can plug in x in the equation y=2x-7:

y=8-7=$\boxed1$