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# find the lines slope and a point on the line. y+5=1/3(x-4)

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find the lines slope and a point on the line.
y+5=1/3(x-4)

Slope:

point on the line:

Mar 3, 2021

#1
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using y=mx+b, we find the lines equation is 1/3x-19/3, so the slope is 1/3

we find a point by substituting x, so if x is 0, the y coord is -19/3, so a point is (0,-19/3)

Mar 3, 2021
#2
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y+5=1/3 x-4/3

y=1/3 x - 19/3

slope:$\boxed{\frac13}$

point on vertical line: $\boxed{0, -\frac{19}3}$

when x = 0,

y = 1/3 (0)-19/3= -19/3

point on horizontal line: $\boxed{19,0}$

when y=0,

0 = 1/3 x - 19/3

0 = x - 19

x = 19

Mar 3, 2021