find the lines slope and a point on the line. y+5=1/3(x-4)

using y=mx+b, we find the lines equation is 1/3x-19/3, so the slope is 1/3

 

we find a point by substituting x, so if x is 0, the y coord is -19/3, so a point is (0,-19/3)

y+5=1/3 x-4/3

y=1/3 x - 19/3

 

slope:$\boxed{\frac13}$

point on vertical line: $\boxed{0, -\frac{19}3}$

when x = 0,

y = 1/3 (0)-19/3= -19/3

 

point on horizontal line: $\boxed{19,0}$

when y=0,

0 = 1/3 x - 19/3

0 = x - 19

x = 19