(a)
Because the curve C in Figure 3 crosses the x-axis at points A and B, the solutions of the equation are A and B:
y = x(x + 4)(x - 2)
0 = x(x + 4)(x - 2) ...
now solve for x -> x1 = 0, x2 = -4 and x3 = 2
We already know A or B are not zero,
so A = -4 (because A is negative) and B = 2 (because B is positive).