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\(\frac{2\sqrt{2 }}{9801}{\displaystyle \sum _{k=0}^{\infty}}\frac{(4k)!(1103+26930k)}{(k!)^4{396}^{4k}}=\frac{1}{\pi}\)

 Oct 21, 2021
 #1
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can someone help me with this 

 

 

There are 18 red markers and 10 yellow markers. The ratio of red to yellow.

 

what is the answer

 Nov 3, 2021

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