Bitte nur Fragen aus dem Fach Mathematik oder vielleicht auch noch andere Fächer!
Hallo Guest!
Die Antwort steht auf der Website web2.0rechner.de ! Tippe dort diese Rechenaufgabe ein.
_ _ _ _ 0 -> 4! / 2 possibilities = 12 p.
_ _ _ _ 2 -> 12 p. - 3 p. (bc 0) = 9 p.
_ _ _ _ 4 -> 12 p. - 3 p. (bc 0) = 9 p.
____
30 p.
So there are 30 ways.
\((\frac{1}{8})^3 = \frac{1}{512} = 2^a \ |\cdot 512 \\ 1 = 2^{a+9}\)
We can always express 1 as n2 ! Let n be 2:
\(2^0 = 2^{a+9}\)
because if nm + a = nd + k, then it applies m + a = d + k:
0 = a + 9 | - 9
-9 = a
a = -9
That's the only possible solution.
This is incorrect. Two sides have to be larger than the other side (triangle).
a + b > c
a + c > b
b + c > a
If that does not apply, it is not constructible.
Use the 7th row of 'Pascal's triangle'.
Expand and get:
64x6 - 192x5 + 240x4 - 160x3 + 60x2 - 12x + 1
\(\frac{1}{2}=\frac{18.5}{37}\) - values under 18.5 = 18 [ actually 19 if 0 counts ]
7 * $2356 = .........
i guess "inversely proportional" = "anti-proportional".
x * y = k constant
3 * 16 = 48 <<<< k constant
b * x = 48, we know that b = 8
-> 8x = 48 -> x = 6.
Expressing 6 as a fraction: \(x = \frac{6}{1}\).
The remainder would be 11.
