In how many ways can the digits of 45,520 be arranged to form a 5-digit number that is even?
If the last digit is zero then there are ? You answer
If the last digit is not zero then how many are there?
Add them together.
_ _ _ _ 0 -> 4! / 2 possibilities = 12 p.
_ _ _ _ 2 -> 12 p. - 3 p. (bc 0) = 9 p.
_ _ _ _ 4 -> 12 p. - 3 p. (bc 0) = 9 p.
____
30 p.
So there are 30 ways.
