TakahiroMaeda

Sounds like something really went down here, while I have been gone.

First you'd want to simply the numerator, 

Factor m out of $81m^3−25m.$

Which results in $\frac{m(81m^2−25)}{9m+5 }$

Given that the Co-Efficent is 81, the pronumeral (m) is sqaured and 25 is also a Sqaure Number, you may Square Root all of the numerator to produce this: $\frac{m((9m)^2−5^2)}{9m+5}$

Factor using the difference of squares. 

Producing: $\frac{m(9m+5)(9m−5)}{9m+5 }$

Reduce the expression by cancelling the common factors. (See the denominator, [9m+5] and the numerator [m(9m+5)]

$m(9m−5)$

Apply the distributive property. 

$m(9m)+m(−5)$

Simplify

$9m^2+(−5m)$

A Note of Caution here, Make sure you understand that a Positive and a Negative form a NEGATIVE:

$9m^2−\Leftarrow5m$

Ignore the Arrow, it is just a means of Bolding or Stating something worth noting.

$9m^2−5m$

is your Answer.

Good to be back :D

ou yolo it.

LEVEL 2

Subject: Maths

Hints 

S---> P

P ---> F

SJYVN-NKEUVWOGYVN EJWAKNTMJW PJNZGYVT

Nice! You did it

hdaorcrtyo rpwohtoter

For the past 3 times that he has asked you out. I have presummed that you have said No/Maybe. So, why are you hesitating now? Is your love that worthless, that it can be bourght with a necklace? If you like him, go for it. But if you don't, don't force yourself. A Necklace is not worth the unconformable process you will go through if you say yes.

I wonder as well.... However, it is impossible to travel to the past. But possible to the future.

I know right.

Tell me your problem.

Indeed, they are. I have a Burger Tree (Burgeranetia papyrifera) at home.

19.

And, no it isn't 21, because any question posted here, you will expect a logical answer.

$$7(e+3)=42$$

$$7e+21=42$$

$$7e+21(-21)=42(-21)$$

$$7e=21$$

$$e=3$$