I am really bored right now, so I am going to start posting questions that I know the answers to. See if you know them as well.

Using only 5 0's and one type of Mathematical Operator, can you get 120?

TakahiroMaeda
Jun 30, 2014

#2**+5 **

No. You may only use five 0's and only One type of Mathematical Operation.

TakahiroMaeda
Jun 30, 2014

#4**0 **

I'm impressed Chris.

Great question Takahiro.

I'm going to add that one to our "Puzzles" thread.

Thanks Takahiro

Thumbs up from me!

Melody
Jun 30, 2014

#5**0 **

Actually...in some sense, " ! " represents an "operator"........so I actually "cheated" because I used the "+" operator, too......

But I'm willing to forget about it if you are........

CPhill
Jul 1, 2014

#6**+3 **

Aye, Sir CPhill, the skill ye have with zeros be amazing!

Here be other solutions: Though this be three operators.

$$(cos(0) + cos(0) + cos(0) + cos(0) + cos(0))! =120 \\$$

Extending the logic of Sir Alan this be true:

$$(not(0)+not(0)+not(0)+not(0)+not(0))! =120$$

M^{-1}

MorganTud
Jul 1, 2014

#7**0 **

Sir See Phil doth admit to cheating by using 2 fold operators.

Thou uses Cos, ! and + . Doth this mean thou expand upon the truth one and one half times more than Sir SeePhill?

Tis impressed I am on both accounts. Tis wonderous what answers thee both hath salvaged.

Melody
Jul 1, 2014

#8**0 **

Greetings Your Majesty,

It seemeth that only a god knoweth the solution by one operator. I know not the deity which hath such knowledge.

Sir Cphill findeth a solution with two. Perhaps it be all the practice with the zeros of the gods.

In your service.

Morgan Tud M^{-1 }

MorganTud
Jul 1, 2014