A question you can answer.

(0! + 0! + 0! +0! + 0!)! =

(1 + 1 + 1 + 1 + 1)! =

5! =

120

Can we use other numbers as well?  I'm not sure I understand.

No. You may only use five 0's and only One type of Mathematical Operation.

I'm impressed Chris.

Great question Takahiro.

I'm going to add that one to our "Puzzles" thread. 

Thanks Takahiro    

Thumbs up from me!

Actually...in some sense, " ! " represents an "operator"........so I actually "cheated" because I used the "+" operator, too......

But I'm willing to forget about it if you are........

Aye, Sir CPhill, the skill ye have with zeros be amazing!

Here be other solutions: Though this be three operators. 

$$(cos(0) + cos(0) + cos(0) + cos(0) + cos(0))! =120 \\$$

Extending the logic of Sir Alan this be true:

$$(not(0)+not(0)+not(0)+not(0)+not(0))! =120$$

M^-1

Sir See Phil doth admit to cheating by using 2 fold operators.  

Thou uses Cos, ! and +  . Doth this mean thou expand upon the truth one and one half times more than Sir SeePhill?

Tis impressed I am on both accounts. Tis wonderous what answers thee both hath salvaged.

Greetings Your Majesty,

It seemeth that only a god knoweth the solution by one operator. I know not the deity which hath such knowledge.

Sir Cphill findeth a solution with two. Perhaps it be all the practice with the zeros of the gods.

In your service.

Morgan Tud M^-1

Perhaps TakahiroMaedo be such a god. For this fine person doth claim to know of such a divine soution!

Yea, Your Majesty, If this be true, then shall I boweth to Takahiro Maeda-sana, with great respect!

M^-1