Tgfromthe4

Let X be shirt cost, Y be tie cost

X + Y = 43, 4X + 4Y = 172

4X + 2Y = 152

4X + 4Y = 172, subtract equations

-2Y = — 20,

Y = $10, X = $33, check work

4 × 33 + 2 × 10 = 152

132 + 20 = 152

152 = 152, yeah!!!

Total age last year --> 27 * 2 = 54

Total age this year --> 54 + 2 = 56

             8 --> 56

             1 --> 7

             3 --> 21

        Jack's age is 21 yrs old 

Erasers = E

Rulers = R

Pencils = P

        E = R = P     Total = E+R+P

(P-38)+ (E-X) + (R-Y) = 90.

 
        (E - X) = (R - Y) * 2

      (P - 38) = (E-X) - 15.      R=?

     
        (P - 38) = 90 - 3 (R-Y).

            90 - 3 (R-Y) = 2 (R-Y) - 15

             90 + 15 = 5 (R-Y) 

             105 = 5(R-Y)

               21 = R-Y

             42.=E-X

(P - 38) + 42 + 21 + 90       P-38=27  P=65=E=R

1 shirt + 1 tie = $43

2 shirt + 2 tie = $43 * 2

                      = $86

4 shirt + 2 tie = $152

=> 2 shirt = $152 - $86

                = $66

     1 shirt = $66 ÷ 2

                = $33

If #1 [brown removed, green is original]

                  B : G : T = 3 : 2 : 5 = 9 : 6 : 15

If #2 [green removed, brown is original]

                 B : G : T               = 14  : 1 : 15

B : G = 14:6 =  7 : 3 (Ans)                           remaining

                                                                    unchanged 

Before you can solve, you must write simultaneous equations. Let x represent hours, and let y represent pages.
 

y = 5x + 51

y = 15x + 41

Now use substitution to solve the simultaneous equations.

Step 1: Isolate a variable.

The variable y is already isolated in the first equation.

Step 2: Plug the result of Step 1 into the other equation and solve for one variable.

Plug y = 5x + 51 into the other equation, y = 15x + 41, and find the value of x.
 

y  =  15x + 41

5x + 51  =  15x + 41

Plug in y = 5x + 51

–10x + 51

 =  41 Subtract 15x from both sides

–10x =  –10 Subtract 51 from both sides

x  =  1 Divide both sides by –10

Step 3: Plug the result of Step 2 into one of the original equations and solve for the other variable.

Take the result of Step 2, x = 1, and plug it into one of the original equations, such as y = 5x + 51. Then find the value of y.
 

y =  5x + 51

y =  5(1) + 51 Plug in x = 1

y  =  5 + 51 Multiply

y =  56 Add

Step 4: State the solution.

Since x = 1 and y = 56, the solution is (1, 56).

After 1 hour, Cole and Terrence will have each completed 56 pages in their workbooks.

Counting books requires whole numbers. 4/11 books is nonsense.

Re-post with information that makes sense.
 

24 flags altogether.

If Mateo started off with 15 flags, then Sam would have had 3/5 of 15, which is 9.

Mateo: 15, Sam: 9

Then, Mateo gives 3 flags to Sam, and they end up with the same amount of flags.

Mateo: 15–3=12, Sam: 9+3=12

12 is the same as 12, so we’re good there.

So how many flags did they have altogether?

12+12=24

Mateo and Sam had 24 flags altogether.

Greg had 1/3 as many calendar to sell as Kenzo.
g = 1/3k
Get rid of fraction, multiply by 3
3g = k
The two friends decided to share the work evenly. To do that, Kenzo gave 10 calendars to Greg.
g + 10 = k - 10
g = k - 10 - 10
g = k - 20
replace k with 3g
g = 3g - 20
20 = 3g - g
20 = 2g
g = 20/2
g = 10 calendars
then
k = 3(10)
k = 30 calendars
:
What was the total number of calendars?
10 + 30 = 40

Apple - Flavoured sweets = A

Lemon - Flavoured sweets = L

     
    (A - 75) + L    =   6 (A - 75)             ,     ( L - 60) + A = 3A

     A - 75 + L    =   6A  - 450                       L - 60 + A = 3A 

     SA - L     =   375 ---- 1                            2A - L = -60 ---- 2

 Via Elimination  :  1 - 2  :  3A  =  435

                                            A  =  435/3

                                                =  145

                                            L  =  SA - 375

                                                =  725 - 375

                                                =  350

Total no-of sweets = 145 + 390

                              =  495