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Sam had 3/5 as many flags as Mateo. Mateo gave 3 flags to Sam so that they would each have the same amount. How many flags did the two of them have altogether?

 May 11, 2021
 #1
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5/3(x-3) 

I think...

 May 11, 2021
 #2
avatar+32894 
+1

Initially 

s = 3/5 m     <===== sub this into the next equation

 

then

s+3 = m-3

3/5 m + 3 = m-3

6 = 2/5 m

m =15     then   s = 9     total  24 flags

 May 11, 2021
 #3
avatar+4 
0

Sam had 3/5 as many flags as Mateo.
let mateo have x flags
Sam has 3x/5 flags 
Mateo gave 3 flags to Sam so that they would each have the same amount. 
x-3 = 3x/5 +3 
x-3x/5 =3+3 
2x/5 = 6 
2x =30
x=15
mateo has 15 flags

 May 11, 2021
 #4
avatar+281 
+1

24 flags altogether.

If Mateo started off with 15 flags, then Sam would have had 3/5 of 15, which is 9.

Mateo: 15, Sam: 9

Then, Mateo gives 3 flags to Sam, and they end up with the same amount of flags.

Mateo: 15–3=12, Sam: 9+3=12

12 is the same as 12, so we’re good there.

So how many flags did they have altogether?

12+12=24

Mateo and Sam had 24 flags altogether.

 May 13, 2021
 #5
avatar+186 
+1

Simple equations

 

let the number of flags with mateo br x

 

that means number of flags with sam = 3/5 of x or 3x/5

 

now mateo gives 3 to sam to make the flags equal

 

that means now mateo has x-3 flags

 

and sam has 3x/5 + 3 flags

 

also these two things are equal now

 

so we can say

 

3x/5 + 3 = x-3

 

3x/5 - x = -3 - 3

 

-2x/5 = -6

 

we can cut the negative signs both sides now

 

2x/5 = 6

 

2x = 30 and that means x = 15

 

so mateo had 15 flags in starting and sam had

 

(3 x 15) / 5 = 9 flags

 May 13, 2021

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