Sam had 3/5 as many flags as Mateo. Mateo gave 3 flags to Sam so that they would each have the same amount. How many flags did the two of them have altogether?
+37146 Initially
s = 3/5 m <===== sub this into the next equation
then
s+3 = m-3
3/5 m + 3 = m-3
6 = 2/5 m
m =15 then s = 9 total 24 flags
+4 Sam had 3/5 as many flags as Mateo.
let mateo have x flags
Sam has 3x/5 flags
Mateo gave 3 flags to Sam so that they would each have the same amount.
x-3 = 3x/5 +3
x-3x/5 =3+3
2x/5 = 6
2x =30
x=15
mateo has 15 flags
+318 24 flags altogether.
If Mateo started off with 15 flags, then Sam would have had 3/5 of 15, which is 9.
Mateo: 15, Sam: 9
Then, Mateo gives 3 flags to Sam, and they end up with the same amount of flags.
Mateo: 15–3=12, Sam: 9+3=12
12 is the same as 12, so we’re good there.
So how many flags did they have altogether?
12+12=24
Mateo and Sam had 24 flags altogether.
+197 Simple equations
let the number of flags with mateo br x
that means number of flags with sam = 3/5 of x or 3x/5
now mateo gives 3 to sam to make the flags equal
that means now mateo has x-3 flags
and sam has 3x/5 + 3 flags
also these two things are equal now
so we can say
3x/5 + 3 = x-3
3x/5 - x = -3 - 3
-2x/5 = -6
we can cut the negative signs both sides now
2x/5 = 6
2x = 30 and that means x = 15
so mateo had 15 flags in starting and sam had
(3 x 15) / 5 = 9 flags
