Sam had 3/5 as many flags as Mateo. Mateo gave 3 flags to Sam so that they would each have the same amount. How many flags did the two of them have altogether?
s = 3/5 m <===== sub this into the next equation
s+3 = m-3
3/5 m + 3 = m-3
6 = 2/5 m
m =15 then s = 9 total 24 flags
Sam had 3/5 as many flags as Mateo.
let mateo have x flags
Sam has 3x/5 flags
Mateo gave 3 flags to Sam so that they would each have the same amount.
x-3 = 3x/5 +3
2x/5 = 6
mateo has 15 flags
24 flags altogether.
If Mateo started off with 15 flags, then Sam would have had 3/5 of 15, which is 9.
Mateo: 15, Sam: 9
Then, Mateo gives 3 flags to Sam, and they end up with the same amount of flags.
Mateo: 15–3=12, Sam: 9+3=12
12 is the same as 12, so we’re good there.
So how many flags did they have altogether?
Mateo and Sam had 24 flags altogether.
let the number of flags with mateo br x
that means number of flags with sam = 3/5 of x or 3x/5
now mateo gives 3 to sam to make the flags equal
that means now mateo has x-3 flags
and sam has 3x/5 + 3 flags
also these two things are equal now
so we can say
3x/5 + 3 = x-3
3x/5 - x = -3 - 3
-2x/5 = -6
we can cut the negative signs both sides now
2x/5 = 6
2x = 30 and that means x = 15
so mateo had 15 flags in starting and sam had
(3 x 15) / 5 = 9 flags