Sam had 3/5 as many flags as Mateo. Mateo gave 3 flags to Sam so that they would each have the same amount. How many flags did the two of them have altogether?

Guest May 11, 2021

#2**+1 **

Initially

s = 3/5 m <===== sub this into the next equation

then

s+3 = m-3

3/5 m + 3 = m-3

6 = 2/5 m

m =15 then s = 9 total 24 flags

ElectricPavlov May 11, 2021

#3**0 **

Sam had 3/5 as many flags as Mateo.

let mateo have x flags

Sam has 3x/5 flags

Mateo gave 3 flags to Sam so that they would each have the same amount.

x-3 = 3x/5 +3

x-3x/5 =3+3

2x/5 = 6

2x =30

x=15

mateo has 15 flags

jiejxu May 11, 2021

#4**+1 **

24 flags altogether.

If Mateo started off with 15 flags, then Sam would have had 3/5 of 15, which is 9.

Mateo: 15, Sam: 9

Then, Mateo gives 3 flags to Sam, and they end up with the same amount of flags.

Mateo: 15–3=12, Sam: 9+3=12

12 is the same as 12, so we’re good there.

So how many flags did they have altogether?

12+12=24

Mateo and Sam had 24 flags altogether.

Tgfromthe4 May 13, 2021

#5**+1 **

Simple equations

let the number of flags with mateo br x

that means number of flags with sam = 3/5 of x or 3x/5

now mateo gives 3 to sam to make the flags equal

that means now mateo has x-3 flags

and sam has 3x/5 + 3 flags

also these two things are equal now

so we can say

3x/5 + 3 = x-3

3x/5 - x = -3 - 3

-2x/5 = -6

we can cut the negative signs both sides now

2x/5 = 6

2x = 30 and that means x = 15

so mateo had 15 flags in starting and sam had

(3 x 15) / 5 = 9 flags

KINGCASH May 13, 2021