Please help, thank you

I agree, this is a really confusing question.

Let                             Melville start with M                and      Danny start with D

Melville give danny 2/5 of his so

afer that                      Melville has 3/5M                  and      Danny has    D+2/5M

Now Danny gives Melville half of what he has

so now        Melville has          3/5M+1/2(D+2/5M)   and      Danny has    1/2(D+2/5M)

Now Melville has 3 times more than Danny

$\frac{3M}{5}+\frac{1}{2}(D+\frac{2M}{5})=3(\frac{1}{2}(D+\frac{2M}{5})\\ 10*[\frac{3M}{5}+\frac{1}{2}(D+\frac{2M}{5})]=10*[3(\frac{1}{2}(D+\frac{2M}{5}))]\\ 6M+5D+2M=15D+6M\\ 8M+5D=15D+6M\\ M=5D$

Melville gave Danny    $\frac{2M}{5}=\frac{2*5D}{5}=2D$

Danny gave Melville    $0.5(D+\frac{2M}{5})=\frac{5D+2M}{10}=\frac{5D+2*5D}{10}=\frac{15D}{10}=\frac{3D}{2}$

We are told that Melvin gave Danny 28 more water guns than what Danny gave to Melvin (though it is worded badly)

$\frac{3D}{2}+28=2D\\ 3D+56=4D\\ D=56$

So Danny started with 56 water guns.

I leave it to you to check.

LaTex

\frac{3M}{5}+\frac{1}{2}(D+\frac{2M}{5})=3(\frac{1}{2}(D+\frac{2M}{5})\\

10*[\frac{3M}{5}+\frac{1}{2}(D+\frac{2M}{5})]=10*[3(\frac{1}{2}(D+\frac{2M}{5}))]\\
6M+5D+2M=15D+6M\\
8M+5D=15D+6M\\
M=5D

You spelled Melvin wrong