thelizzybeth

There was a typo. I edited my answer and now it should be correct. However, if you understood my method and actually read the solution, not just the answer, you should have seen where I went wrong. 

It's fine if you don't understand my solution- just ask. 

Let's say our new line is y=mx+b, where m is the slope and b is the y-intercept.

First put the equation in slope-intercept form. y=8x-7

Parallel lines have the same slope. Our equation is now y=8x+b

Plug the point (5, -3) in.

-3=8*5+b

b=-43

So the equation of the line in slope-intercept form is y=8x-43.

If the question is asking for standard equation, then it would be 8x-y=43

Did you type something wrong? There are five letters and five envelopes.

Yes. For example, in the expression \(5x^3+10x^2+8x+9\), there are four terms.

2) When you put 3 into f(x), you get 1. When you put 1 into f(x), you get 5. So one point in f(x(x)) is (3,5).

When you put 2 into f(x), you get 3. When you put 3 into f(x), you get 1. So the second point on f(x(x)) is (2,1).

3*5+2*1=17

Whew! XD

Thank you! :)