+310 Let \(p(x)\) be defined on \(2 \le x \le 10\) such that
\(p(x) = \begin{cases} x + 1 &\quad \lfloor x \rfloor\text{ is prime} \\ p(y) + (x + 1 - \lfloor x \rfloor) &\quad \text{otherwise} \end{cases}\)
where \(y\) is the greatest prime factor of \(\lfloor x\rfloor.\) Express the range of \(p\) in interval notation.
The function gets bumped up at every prime values, so the range of p is [2,5] U [8,9].
+310 Sorry, that's incorrect. Can you expand more behind your reasoning so I can attempt your method myself?
