Find the equation of the line passing through (5,-3) that is parallel to the line 8x - y = 7.
+310 Let's say our new line is y=mx+b, where m is the slope and b is the y-intercept.
First put the equation in slope-intercept form. y=8x-7
Parallel lines have the same slope. Our equation is now y=8x+b
Plug the point (5, -3) in.
-3=8*5+b
b=-43
So the equation of the line in slope-intercept form is y=8x-43.
If the question is asking for standard equation, then it would be 8x-y=43
