+0  
 
-1
156
6
avatar+112 

For what value of k does the equation x^2+10x+y^2+6y-k=0 represent a circle of radius 6?

 Jun 25, 2020
edited by QuestionsBug  Jun 25, 2020
 #1
avatar+2152 
0

The question isn't complete :(

 Jun 25, 2020
 #2
avatar+46 
+2

I seriously don't understand why so many people like to copy questions with latex...

 

where do they come from???

 Jun 25, 2020
 #3
avatar+2152 
0

I don't know. Alcumus? 

 

Please write out the question completely... I'll try to help when you do! :D

 Jun 25, 2020
 #4
avatar+112 
0

Yes, I actually got it from alcums, and I also fixed it, sorry.

QuestionsBug  Jun 25, 2020
 #5
avatar+307 
-1

A circle equation is \((x-h)^2+(y-k)^2=r^2\), where (h, k) is the center and r is the radius.

We complete the square for x and y to get it in circle form.

Add 25 and 9 to both sides to complete the square.  \(x^2+10x+25+y^2+6y+9-k=25+9\)

Now we can write the squares. We also k to both sides. \((x+5)^2+(y+3)^2=34+k\)

It's in circle equation now!

Since the radius must be 6, 34+k=36. 

k=2

 Jun 25, 2020
 #6
avatar+112 
0

Thank you so much! :)

QuestionsBug  Jun 25, 2020

40 Online Users