Vraces

10^x - 0.8 * 10^x = 20

10^2x + 0.2 = 20

10^2x = 4

10^x = 2

I still don't understand how + 0.2 can be multiplied to the other side ( 20 ).

Surely I can get the answer, but if I don't learn the purpose of w*f I'm doing, then I will not be able to mathematically evolve.

Thank you for your effort, and I'm sorry to take so much of your time.

I know. Can you give me one very similiar to this one and I'll see if I can solve it.

I understand this example perfectly clear. But I'm having some problem factoring on logarithms.

I understand. But how do you remove the 10^x. I understand you are factoring out, but how doesn't this break against equation laws? Everything you change on < side you have to change on > side. For example

3x + 3 = 10

3x = 7

I understand the result and the last part. But what do you mean by (1)? What rules allow this 1 to come from nowhere and what rule allows 10^x to be removed because there is another 10^x? Maybe I lack the basics or something?

Sorry. You'll have to explain this on a retard level.

I don't understand how the subtraction with one happens and why it turns into 0.02 instead of 0.2.

Thank you for replying.

Can you explain how and why 1 is subtracted with 0.2?

But how does 4 - 4  = 4. Can you explain what this means in the magic land of math?