In a magical triangle, angle A is 90°, angle B is 38°
A bisector to angle C hits the distance AB at point D
Calculate angle ACD
Now obviously, the bisector of C is 26° but why would angle ACD = 26°? This makes no sense to me. If you can explain that'd be great. I think there some kind of math rule I haven't understood yet. Like for e.g. What does angle ACD actually mean. Is it all the angles combined or w*f. Anyways, let me know.
Notice that [A = 90] + [ B = 38] = 128 degrees.
Since the three interior angles of a triangle measure 180.....angle C must measure the other 52 remaining degrees. But an angle bisector would cut this in half.....so 1/2 of 52 = 26 degrees....
Note the triangle below - not to scale !!!..... ACD is the angle formed when ACB is bisected...
"ACD" refers to the angle formed by the points ....well....A,C and D in that order....So ACB would be 52 degrees, ACD = 26 and DCB = 26, since angle C is bisected.....
Does that make sense ???