Weiart000

Oh wow! Great work! Wow you also beat me to solving this! I'm not very sure about my answer...

Not sure about this, but first, find the area of the circle (121 pi). Then, because it is a 300 degree arc, the part you want to find is 5/6 of the circle. This would then be (121 pi)(5/6), which would be easy to solve.

To solve this equation:

(1-2)+(3-4)+...+(2013-2014) = -1(x) you can figure it out from here.

Um... is this supposed to be a question?

Well, for substitution, it's very simple:

3x + 6(-5) = -18

3x + (-30) = -18

3x = 12

x = 4

Then, for elimination it would be:

(-7x + 9y = -19)

+ (4x -9y = 10)

------------------------

-3x = -9

x = 3

And finally, for the other elimination:

(-5x + 8y = -4)

+ (6x - 8y = -12)

---------------------

x = -16

I am not sure if this is the "right" kind of elimination, but it works!

Wait, who's that?

Oh ok thanks!

If ATQ = 41, and AUR = 63, then find QXR, in degrees.

Sorry, I realized I can't use the angle sign...