To cancel \(ab\) you can add the equations together:
\(2a=10 \Rightarrow a=\color{blue}{\boxed{5}}\)
Now plug in \(a\) into one of the equations to get:
\(5+5b=250 \Rightarrow 5b=245 \ \text{so} \ b=\color{blue}{\boxed{49}}\).
I hope that helped!
The only solution works out to be \(x=2\).
Put the terms with \(x\) on one side and the numbers on the other:
\(2x+x+7x \le 12+18+5\)
which simplifies to \(10x\le35\)
So \(x= \dfrac{7}{2}\).
First, simplify the function to: \(x=2y^2-13y-1\)
Setting \(x'=0\), \(4y-13=0\) so \(y=\dfrac{13}{4}\). Your next step is to find \(x\). Then \((x,y)\) is the vertex.
Good answer.
Go to https://web2.0calc.com/questions/help_81031 for help
Hi guest,
Go to https://web2.0calc.com/questions/please-help_66976 for explanation.
But anyways:
2y + z
x = ______
y - 3
Anyways, \(\boxed{n=3}\)
I suggest you go to this link. : https://web2.0calc.com/questions/counting_38343
\(x=120\) \(240000=2000x \) \(\dfrac{2000}{60}=\dfrac{6000}{x}\)
Thanks, I bumped into the same promblem and this helped alot.