Hi, in this type of questions we always follow these steps:
Step 1: let the a variable be equal to this expression.
For instance,
x=√12+√12+...
Step 2: Square both sides:
x2=12+√12+...
But, notice, x was defined to be these "squareroots" right?
So: x2=12+x
Step 3: We solve this equation.
x2=12+x⟺x2−x−12=0⟺(x−4)(x+3)=0⟺x=4Note: We rejected x=-3 as we know x>0 (as the squareroot of any number is non-negative)
draw[blue, very thick] (0,0) rectangle (3,2)Thanks, now I get it.
Well the next promblem is
√12−√12−√12−⋯