solve for x in terms of y and z, assuming y does NOT equal 3:
xy=3x+2y+z
thanks! i'm rly having trouble :((
First we get all x on one side: xy-3x = 2y+z
Then we factor x on the left hand side: x(y-3)
then divide by y-3
right, but what about the right side? is it just 2y+z / y-3?
xy = 3x + 2y + z rearrange as
xy - 3x = 2y + z factor out x on the left
x ( y - 3) = 2y + z divide both sides by (y - 3)
2y + z
x = ______
y - 3
+120 
