Find the vertex of the graph of the equation $x - y^2 + 8y = 13 + 2y + y^2 - 7y - 14$.
First, simplify the function to: \(x=2y^2-13y-1\)
Setting \(x'=0\), \(4y-13=0\) so \(y=\dfrac{13}{4}\). Your next step is to find \(x\). Then \((x,y)\) is the vertex.
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